Test

This is from Canvas

This is a trial – Heading 2

paragraph

Heading 3

some text

Heading 4

some text. some text that’s bolded. Some text that is underlined. 

Numbered list:

  1. number 1
  2. number 2

Bullet list:

  • Bullet 1
  • Bullet 2
This is a test table
Column 1 Column 2 centered

 

This is an annotated image of an equation. The first is a fraction of x over 3 equals a capital greek letter d and

LaTeX: \frac{5}{4}-y=x^4\frac{x^4}{z_3}\times\delta4.3

 

 

 

Exponential Notation

This is exponential notation where the small number written above and to the right of the base (superscript), indicating how many times the base is multiplied by itself. (example: 23 = 2 x 2 x 2)

this is a image showing exponential notation 

This is a table showing exponential numbers, the operations, and the ordinary number.
Exponential Number What is happening Ordinary Number
1 x 106 10 x 10 x 10 x 10 x 10 x 10 1,000,000
1 x 103 10 x 10 x 10 1,000
1 x 102 10 x 10 100
1 x 101 10 10
1 x 100 1 (anything raised to 0 power is 1) 1
1 x 10-1 LaTeX: \frac{1}{10} 0.1
1 x 10-2 LaTeX: \frac{1}{10} x LaTeX: \frac{1}{10} 0.01
1 x 10-3 LaTeX: \frac{1}{10} x LaTeX: \frac{1}{10} x LaTeX: \frac{1}{10} 0.001
1 x 10-6 LaTeX: \frac{1}{10} x LaTeX: \frac{1}{10} x LaTeX: \frac{1}{10} x LaTeX: \frac{1}{10} x LaTeX: \frac{1}{10} x LaTeX: \frac{1}{10} 0.000 001

Scientific Notation

This is standard scientific notation where only significant digits are shown and the decimal is after the first digit. This is followed by a multiplication sign, and then 10, and then the power of 10 in superscript. (example: 3.250 x 103 = 3.250 x 10 x 10 x 10 = 3,250)

This is an image of standard scientific notation

 

Metric Units

This is a table of commonly used metric units.

What you are measuring

Base Unit

Symbol

Length

meter

m

Mass

kilogram

kg

Volume

liter

L

Temperature

kelvin

K

Time

seconds

s

Amount of something

mole

mol

 

 

 

 

 

 

Metric Prefixes

This is a table of common metric prefixes and their symbols, meaning, and examples.
Prefix Abbreviation Meaning Example
tera T 1,000,000,000,000 or 1012 1 teragram (Tg) = 1012 g
giga G 1,000,000,000 or 109 1 gigameter (Gm) = 109 m
mega M 1,000,000 or 106 1 megaliter (ML) = 106 L
kilo k 1,000 or 103 1 kilosecond (ks) = 1,000 s
hecto h 100 or 102 1 hectomole (hmol) = 100 mol
deka da 10 or 101 1 dekakelvin (daK) = 10 kelvin
1 1 gram (g) or any unit
deci d 1/10 or 0.1 or 10-1 1 decimeter (dm) = 0.1 m
centi c 1/100 or 0.01 or 10-2 1 centiliter (cL) = 0.01 L
milli m 1/1,000 or 0.001 or 10-3 1 millisecond (ms) = 0.001 s
micro m 1/1,000,000 or 10-6 1 micromole (mmol) = 10-6 mol
nano n 1/1,000,000,000 or 10-9 1 nanogram (ng) = 10-9 g
pico p 1/1,000,000,000,000 or 10-12 1 picokelvin (pK) = 10-12 K

 

Common Conversions

This is a table of common conversions.
Conversion Factors / Conversion Rates Description (can convert the reverse as well)
1 milliliter (mL) = 1 centimeter cubed (cm3) or (cm x cm x cm) use to convert a milliliter (mL) volume to a centimeter cubed (cm3) volume  
1 liter (L) = 1000 centimeter cubed (cm3) or (cm x cm x cm) use to convert a liter (L) volume to a centimeter cubed (cm3) volume 
1 inch (in) = 2.54 centimeters (cm) use to convert from inches (standard system) to centimeters (metric system)
1 yard (yd) = 0.9144 meters (m) use to convert from yard (standard system) to meters (metric system)
454 grams (g) = 1 pound (lb)  use to convert grams (metric system) to pounds (standard system)
0.946 liters (L) = 1 quart (qt) use to convert liters (metric system) to quarts (standard system)
1 mole = 6.022 x 1023 things (usually atoms or molecules) can use this to convert in and out of moles (moles to atoms or molecules)

Test1

Test 2

Introduction

Chemistry requires the use of various math operations including algebra. A common reason why students struggle to be successful in chemistry is their math skills are not sufficient for chemistry. Students then have to learn complex chemistry concepts and calculations as well as math at the same time. This will help students learn the math fundamentals to be successful in chemistry.

Contents

·         Part A: Identification of the parts of an equation

o   Example A1: Identification of the parts of an equation

§  Practice A1: Identification of the parts of an equation

§  Practice A2: Infer the “hidden” parts of an equation

·         Part B: Isolate a variable

o   Example B1: Identify the math operation and opposite operation to isolate the variable

§  Practice B1: Identify the math operation and opposite operation to isolate the variable

o   Example B2: Solve for a variable (addition/subtraction)

§  Practice B2: Solve for a variable

o   Example B3: Solve for a variable (addition/subtraction)

§  Practice B3: Solve for a variable

o   Example B4: Solve for a variable (multiplication/division)

§  Practice B4: Solve for a variable

o   Example B5: Solve for a variable (multiplication/division)

§  Practice B5: Solve for a variable

·         Multiple operations

o   Example B6: Solve for a variable (exponents/roots)

§  Practice B6: Solve for a variable

o   Example B7: Solve for a variable (exponents/roots)

§  Practice B7: Solve for a variable

·         Multiple operations

o   Example B8: Solve for a variable (variable in exponent/logarithms)

§  Practice B8: Solve for a variable

o   Example B9: Solve for a variable (natural log)

§  Practice B9: Solve for a variable

o   Example B10: Solve for a variable (ex)

§  Practice B10: Solve for a variable

·         Multiple operations

 

·         Exercises

·         Answer Key to Practice Problems

·         Answer Key to Exercises

Part A: Identification of the parts of an equation

In chemistry we often use variables. A variable is usually a letter or symbol used in equations that can have different values. Figure 1A shows an equation with name labels in the left figure below. If there is no fraction bar, the number is considered to be a numerator with an imaginary fraction bar and a 1 in the denominator (Figure 1B).

Example A1: Identification of the parts of an equation

AA diagram of mathematical equations

Description automatically generated

BA diagram of numbers and symbols

Description automatically generated

Figure 1: (A) Figure showing various names of objects in an equation (left). (B) The same equation but including the imaginary fraction bars and the numbers 1 in the denominators (right).

Practice A1: Identify the parts of an equation

Label the following parts of this equation:

·         Numerators

·         Denominators

·         Equal sign

·         Variables

·         Fraction Bar

·         Operation symbols

 

A mathematical equation with numbers and symbols

Description automatically generated

Practice A2: Infer the “hidden” parts of an equation

 

Write-in the imaginary fraction bars and imaginary 1’s in the denominators

 

 

A mathematical equation with numbers and symbols

Description automatically generated

Part B: Isolate a variable

We routinely solve for variables in chemistry. This means get the variable by itself on one side of the equation symbol. This also means get the variable on top of the fraction bar in the numerator position. How do we get the variable “y” by itself on one side of the equation in the numerator position? To do this you must do the opposite of the operation it currently is associated with. Also, for the equation to remain correct, you must perform whatever opposite operation is needed to both sides of the equal sign. Table 1 shows a column of math operations on the left and the corresponding opposite operation.

Math Operation

Opposite of Operation

Addition

Subtraction

Subtraction

Addition

Multiplication (in the numerator)

Division

Division (in the denominator)

Multiplication

x2 (Squared)

Square root or raise to the 1/2 power

X3 (Cubed)

Cubed root or raise to the 1/3 power

anythingx (exponent)

log (x) (logarithm)

ln (x) (natural log)

ex (Euler’s number)

Table 1: A list of math operations (left) as well as the corresponding opposite math operation (right).

Example B1: Identify the math operation and opposite operation to isolate the variable

Equation

Operation that the variable is involved in

Opposite operation to isolate the variable

<img src="https://latex.codecogs.com/svg.image?&space;y-3=6" title=" y-3=6" />

3 is being subtracted from y

You must add 3

9 is being added to n

You must subtract 9

7 is being multiplied by x

You must divide by 7

 

 

X is being raised to the 3rd power

You must take the cubed root of X or raise to the 1/3 power

X is being squared

You must raise this to

 

 

ln (x)

 

 

Practice B1: Identify the math operation and opposite operation to isolate the variable

Equation

Operation that the variable is participating in

Opposite operation to isolate the variable

3 is being subtracted from y

You must add 3

9 is being added to n

You must subtract 9

7 is being multiplied by x

You must divide by 7

 

 

 

 

 

 

 

 

 

 

Example B2: Solve for a variable (addition/subtraction)

Problem:

Solve for “y”

 

 

 

Equation:

 

Step 1:

+

Add 3 to both sides of the equation.

Explanation:

 

Since 3 is initially being subtracted from “y” on the left size, 3 must be added to “y” (addition is the opposite operation of subtraction) to remove the “ – 3 “ on the left side and get the variable “y” by itself. Add 3 to both sides of the equation because the same operation must be performed to both sides of the equation for the equation to remain true.

 

On the left side of the equation symbol, +3 and -3 equal 0

 

Since subtracting or adding 0 to something doesn’t change it’s value, you can just leave 0 out.

 

Problem:

Solve for “y”

 

 

 

Equation:

 

Step 1:

Add 3 to both sides of the equation.

Explanation:

 

Since 3 is initially being subtracted from “y” on the left size, 3 must be added to “y” (addition is the opposite operation of subtraction) to remove the “ – 3 “ on the left side and get the variable “y” by itself. Add 3 to both sides of the equation because the same operation must be performed to both sides of the equation for the equation to remain true.

 

On the left side of the equation symbol, +3 and -3 equal 0

 

Since subtracting or adding 0 to something doesn’t change it’s value, you can just leave 0 out.

 

Practice B2: Solve for a variable

Example B3:

Problem:

Solve for “n”

 

 

 

Equation:

 

Step 1:

Subtract 9 from both sides of the equation.

Explanation:

 

Since 9 and “n” are being added together, 9 must be subtracted from the right side (subtraction is the opposite operation of addition) to remove the 9 on the right side and get the variable “n” by itself. Subtract 9 from both sides of the equation because the same operation must be performed to both sides of the equation for the equation to remain true.

 

On the right side of the equation symbol, +9 and -9 equal 0

 

Since subtracting or adding 0 to something doesn’t change it’s value, you can just leave 0 out.

Example B4:

Problem:

Solve for “x”

 

 

 

Equation:

 

Step 1:

Divide 7 from both sides of the equation.

Explanation:

 

Since 7 and “x” are being multiplied together, 7 must be divided from the left side (division is the opposite operation of multiplication) to remove the 7 on the right side and get the variable “x” by itself. Divide 7 from both sides of the equation because the same operation must be performed to both sides of the equation for the equation to remain true.

 

On the left side of the equation symbol, +9 and -9 equal 0

 

Since multiplying or dividing something by 1 doesn’t change it’s value, you can just leave 1 out.

 

 

 

Part B: Get a variable into the numerator position

Text

Part C: Multiple operations to solve for a variable

Text

Lesson 3: Simplifying

Text

 

Notes:

·         Practice in each section

o   Y=mx+b

§  Curved lines with e

o   PV=nRT

o   Temp conversions

·         Do all operations

·         Do multi-variable operations

o   Have to distribute for various things

o   Pemdas???

 

Exercises:

Lesson 1:

Lesson 2:

Lesson 3:

 

 

Introduction    

Chemistry requires the use of various math operations including algebra. A common reason why students struggle to be successful in chemistry is their math skills are not sufficient for chemistry. Students then have to learn complex chemistry concepts and calculations as well as math at the same time. This will help students learn the math fundamentals to be successful in chemistry.

Contents

  • Part A: Identification of the parts of an equation
    • Example A1: Identification of the parts of an equation
      • Practice A1: Identification of the parts of an equation
      • Practice A2: Infer the “hidden” parts of an equation
  • Part B: Isolate a variable
    • Example B1: Identify the math operation and opposite operation to isolate the variable
      • Practice B1: Identify the math operation and opposite operation to isolate the variable
    • Example B3: Solve for a variable (addition/subtraction)
      • Practice B3: Solve for a variable
  • Multiple operations
  • Example B6: Solve for a variable (exponents/roots)
    • Practice B6: Solve for a variable
    • Example B7: Solve for a variable (exponents/roots)
      • Practice B7: Solve for a variable
  • Multiple operations
    • Example B8: Solve for a variable (variable in exponent/logarithms)
      • Practice B8: Solve for a variable
    • Example B9: Solve for a variable (natural log)
      • Practice B9: Solve for a variable
    • Example B10: Solve for a variable (ex)
      • Practice B10: Solve for a variable
  • Multiple operations
  • Exercises
  • Answer Key to Practice Problems
  • Answer Key to Exercises

Part A: Identification of the parts of an equation

In chemistry we often use variables. A variable is usually a letter or symbol used in equations that can have different values. Figure 1A shows an equation with name labels in the left figure below. If there is no fraction bar, the number is considered to be a numerator with an imaginary fraction bar and a 1 in the denominator (Figure 1B).

Example A1: Identification of the parts of an equation

AA diagram of mathematical equations

Description automatically generatedBA diagram of numbers and symbols

Description automatically generated

Figure 1: (A) Figure showing various names of objects in an equation (left). (B) The same equation but including the imaginary fraction bars and the numbers 1 in the denominators (right).

Practice A1: Identify the parts of an equation

Label the following parts of this equation: NumeratorsDenominatorsEqual signVariablesFraction BarOperation symbols  A mathematical equation with numbers and symbols

Description automatically generated

Practice A2: Infer the “hidden” parts of an equation

  Write-in the imaginary fraction bars and imaginary 1’s in the denominators    A mathematical equation with numbers and symbols

Description automatically generated

Part B: Isolate a variable

We routinely solve for variables in chemistry. This means get the variable by itself on one side of the equation symbol. This also means get the variable on top of the fraction bar in the numerator position. How do we get the variable “y” by itself on one side of the equation in the numerator position? To do this you must do the opposite of the operation it currently is associated with. Also, for the equation to remain correct, you must perform whatever opposite operation is needed to both sides of the equal sign. Table 1 shows a column of math operations on the left and the corresponding opposite operation.

Math OperationOpposite of Operation
AdditionSubtraction
SubtractionAddition
Multiplication (in the numerator)Division
Division (in the denominator)Multiplication
x2 (Squared)Square root or raise to the 1/2 power
X3 (Cubed)Cubed root or raise to the 1/3 power
anythingx (exponent)log (x) (logarithm)
ln (x) (natural log)ex (Euler’s number)